标题: 高数问题~帮我解答下~~又加了两题~ [打印本页] 作者: LATER 时间: 2012-3-22 05:07 PM 标题: 高数问题~帮我解答下~~又加了两题~ 本帖最后由 LATER 于 2012-3-24 09:08 AM 编辑
find the value of a and d(arithmetic progression)
T2+T3=29
S6-S4=71
更新~
1)given that 3,m,n,192 are the first four consecutive terms of a geometric progression.find the three consecutive terms which added up to 16128~~
2)the price of a new car is RM80000.It is given that the price of the car depreciates at a constant rate of 5% yearly.Calculate the minimum number of years required for the price of the car to drop to less than RM45000.作者: caviiy 时间: 2012-3-22 05:11 PM
问题就这样???作者: LATER 时间: 2012-3-22 05:12 PM 回复 2#caviiy
答案对了~谢谢~
还有一题~能不能帮忙解解看~
the sum of the first terms of an a.p is given by Sn=3n2-5n.find the first term作者: suki89 时间: 2012-3-22 05:47 PM
a=4, d=7.作者: xlwenlx 时间: 2012-3-22 05:49 PM 回复 5#LATER
没有a或d吗?作者: LATER 时间: 2012-3-22 05:50 PM 回复 7#xlwenlx
答案对了哦~能不能帮我解多一题~题目在5楼~谢谢
LATER 发表于 2012-3-22 06:04 PM
用n=1 就找到答案了作者: LATER 时间: 2012-3-24 09:06 AM 回复 10#南湘楚
还有这两题怎么做~
1)given that 3,m,n,192 are the first four consecutive terms of a geometric progression.find the three consecutive terms which added up to 16128~~
2)the price of a new car is RM80000.It is given that the price of the car depreciates at a constant rate of 5% yearly.Calculate the minimum number of years required for the price of the car to drop to less than RM45000.